Answer :

Given: A = {2, 4, 8, 12}, B = {1, 2, 3, 4}, C = {4, 8, 12, 14}, D = {3, 1, 4, 2}

E = {–1, 1}, F = {0, a}, G = {1, –1}, H = {0, 1}

As we see,

8 Є A, but 8 does not belong to B,D,E,F,G and H

⇒ A≠B, A≠D, A≠E, A≠F, A≠G, A≠H

And 2 Є A but 2 does not belong to C

⇒ A≠C.

Now, 3 Є B, but 3 does not belong to C,E,F,G and H

⇒ B≠C, B≠E, B≠F, B≠G, B≠H

Also, 12 Є C, but 12 does not belong to D,E,F,G and H

⇒ C≠D, C≠E, C≠F, C≠G, C≠H

Also, 4 Є D, but 4 does not belong to E,F,G and H

⇒ D≠E, D≠F, D≠G, D≠H

Also, -1 Є E, but -1 does not belong to F,G and H

⇒ E≠F, E≠G, E≠H

Also, a Є F, but a does not belong to G and H

⇒F≠G, F≠H

Also, -1 Є G, but -1 does not belong to H

⇒ G≠H

But B = D and E = G.

As, Two set A and B are said to be equal if they have exactly same elements then we say A = B.

Because elements of set (B and D) and (E and G) do not have significant order but (B and D) and (E and G) have same element.

∴ B = D and E = G.

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