Q. 95.0( 1 Vote )

# Find the equation

Given equation:

y = x3 + 2x - 4

On differentiating with respect to x

…(1)

It is to the line x + 14y + 3 = 0

The slope of the line is

The slope of the tangent is

m1 = 14

…(2)

Equating equ(1) and equ(2)

3x + 2 = 14

3x = 12

x = 4

y = (4)3 + 2(4) - 4

= 64 + 8 - 4

= 68.

Point of contact is (x,y) = (4,68)

Equation of the tangent is y−y1 = m(x−x1)

y−68 = 14(x−4)

y−68 = 14x−64

14x - y + 4 = 0

This is the required equation.

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