Q. 95.0( 1 Vote )

Find <span lang="

Answer :


Using the identities 1 = sin2x + cos2x,


sin 2x = 2 sin x cos x


cos 2x = cos2x – sin2x



Using (a + b)2 = a2 + 2ab + b2







We know that ∫ex[f(x) + f’(x)] dx = ex f(x) + c


Here f(x) = sec x hence f’(x) = sec x tan x


Hence ∫ex [sec x + sec x tan x] dx = ex sec x + c


I = (1/2)ex sec x + c


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