Answer :

Given that,

CQ: QP = 3: 1

Let,

CQ = 3x

PQ = x

Area ( = 10 cm^{2}

We know that,

Area of triangle = * Base * Height

Area ( = * x * h

10 = * x * h

x * h = 20

Area ( = * 3x * h

= * 3 * 20

= 30 cm^{2}

Now,

Area ( = * PB * H = 30 cm^{2}

PB * H = 60 cm^{2}

We have to find area of parallelogram

We know that,

Area of parallelogram = Base * Height

Area ( = AB * H

Area ( = 2 BP * H

Area (ABCD) = 2 (60)

Area (ABCD) = 120 cm^{2}

Hence,

Area of parallelogram ABCD is 120 cm^{2}

Rate this question :

The lengths of thRS Aggarwal & V Aggarwal - Mathematics

In Q. No. 1, if ARD Sharma - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal & V Aggarwal - Mathematics

ABCD is a paralleRD Sharma - Mathematics

In Δ ABC, ERD Sharma - Mathematics

P is the mid-poinRD Sharma - Mathematics

Diagonals of a quRD Sharma - Mathematics