Answer :
The given data can be formulated in a table as below.
Let, required production of product A, B and C be x, y and z units respectively.
Given, profit on one unit of product A, B and C are Rs 3, and Rs 2, Rs 4.
So, profit on x, y, z units of A, B, C Rs 3x, Rs 2y, Rs 4z.
Let U be the total profit, so
U = 3x + 2y + 4z
Given, one unit of product A, B and C requires 4, 3 and 5 minutes on machine M1. So, x units of A, y units of B and z units of C need 4x, 3y and 5z minutes. Maximum capacity on machine M1 is 2000 minutes, so,
4x + 3y + 5z ≤ 200 0 (First constraint)
Given, one unit of product A, B and C requires 2, 2 and 4 minutes on machine M2. So, x units of A, y units of B and z units of C require 2x, 2y and 4z minutes. Maximum capacity on machine M2 is 2500 minutes, so,
2x + 2y + 4z ≤ 250 0 (Second constraint)
Also, given that firm must manufacture more than 100 A’s, 200 B’s, 50 C’s also not more than 150 A’s, so,
100 ≤ x ≤ 150,
y ≥ 200 (Other constraints)
z ≥ 50
Hence, mathematical formulation of LPP is:
Find x, y and z which maximize U = 3x + 2y + 4z
Subject of constraints,
4x + 3y + 5z ≤ 2000
2x + 2y + 4z ≤ 2500
100 ≤ x ≤ 150,
y ≥ 200
z ≥ 50
and also, as production cannot be less than zero, so x, y ≥ 0
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