Q. 855.0( 1 Vote )


There are three

Answer :


Let the three consecutive positive integers be x, x + 1 and x + 2.
x 2 + (x + 1)(x + 2) = 154
x 2 + x 2 + 3x + 2 = 154
2x 2 + 3x - 152 = 0
2x 2 + 19x – 16x – 152 = 0
x(2x + 19) – 8(2x + 19) = 0
(x – 8)(2x + 19) = 0
x = 8 or

The integers are 8, 9 and 10.
Checking:
8 2 + 9 × 10 = 64 + 90 = 154.

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