Answer :

Part I : 5x + 2 < 3x + 8

2x < 6


x < 3


Part II :





Case I : -3x + 6 < 0 and x – 1 > 0


x > 2 and x > 1


By taking intersection x (2, ∞)


Case II : -3x + 6 > 0 and x – 1 < 0


x < 2 and x < 1


By takin intersection x (-∞, 1)


Taking union of case I and case II, x (-∞, 1) (2, ∞)


We have to take intersection of part I and part II, we have


final answer i.e., x (-∞, 1) (2, 3)


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Solve each of theRD Sharma - Mathematics

A solution is to RD Sharma - Mathematics

A company manufacRD Sharma - Mathematics

<span lang="EN-USRS Aggarwal - Mathematics

<span lang="EN-USRS Aggarwal - Mathematics

Solve each of theRS Aggarwal - Mathematics

Solve x + 5 > RS Aggarwal - Mathematics

Find the solutionRS Aggarwal - Mathematics

If |x – 1| > 5Mathematics - Exemplar

If x is a real nuMathematics - Exemplar