Q. 85.0( 1 Vote )

Write the distanc

Answer :

We know that, distance between two parallel planes:


Ax + By + Cz + D1=0…… (1) and Ax + By + Cz + D2=0…… (2) is given by,



Here, the two parallel planes are given as,


2x–y + 3z=4 i.e. 2x–y + 3z - 4=0 …………… (3)


and 2x–y + 3z=18 i.e. 2x–y + 3z - 18=0 ………… (4)


Comparing equation (3) with equation (1) and equation (4) with equation (2) we get,


A=2, B= - 1, C=3, D1= - 4 and D2= - 18.


So, the distance between the given two parallel planes are,







Hence, the distance between the parallel planes 2x–y + 3z=4 and 2x–y + 3z=18 is .


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