Q. 85.0( 1 Vote )

# Write the distanc

We know that, distance between two parallel planes:

Ax + By + Cz + D1=0…… (1) and Ax + By + Cz + D2=0…… (2) is given by, Here, the two parallel planes are given as,

2x–y + 3z=4 i.e. 2x–y + 3z - 4=0 …………… (3)

and 2x–y + 3z=18 i.e. 2x–y + 3z - 18=0 ………… (4)

Comparing equation (3) with equation (1) and equation (4) with equation (2) we get,

A=2, B= - 1, C=3, D1= - 4 and D2= - 18.

So, the distance between the given two parallel planes are,     Hence, the distance between the parallel planes 2x–y + 3z=4 and 2x–y + 3z=18 is .

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