C(x) = 0.005x3 – 0.02x2 + 30x + 5000Marginal cost is given by,Cm = (C(x)) Cm = (0.005x3 – 0.02x2 + 30x + 5000)Cm = (0.005 × 3 × x2) – (0.02 × 2 × x) + 30Now it is given that number of units = 3Therefore, x = 3,Cm = (0.005 × 3 × 9) – (0.02 × 2 × 3) + 30 Cm = 30.135 – 0.12 Cm = 30.015

Q. 84.8( 5 Votes )

The total cost C(

Class 12th Mathematics - Board Papers All India - 2018

Answer :

C(x) = 0.005x³ – 0.02x² + 30x + 5000

Marginal cost is given by,

C_m = (C(x))

C_m = (0.005x³ – 0.02x² + 30x + 5000)

C_m = (0.005 × 3 × x²) – (0.02 × 2 × x) + 30

Now it is given that number of units = 3

Therefore, x = 3,

C_m = (0.005 × 3 × 9) – (0.02 × 2 × 3) + 30

C_m = 30.135 – 0.12

C_m = 30.015

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