Answer :

Let S = √2 + √6 + √18 + ……….


It can also be written as,


S = √2(1 + √3 + 3 + 3√3 + …….)


Now,


1 + √3 + 3 + 3√3 + …… is a G.P with common ratio √3


Sum of the 10 terms will be given by,






S10 = 121(√6 + √2)

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