Q. 83.8( 6 Votes )
The parallel sides o
Let ABCD be a trapezium in which
AB = 60 m, CD = 77 m, BC = 26 m, AD = 25 m
Draw BE || to AD
Thus ABED is parallelogram
Hence AB = DE = 60 m.
AD = BE = 25 m
and EC = DC - DE = 77 - 60 = 17 m
Now in ΔBEC,
BE = 25 m, BC = 26m, EC = 17m
Let the height of B from EC be = h m
S = = 34
Area of ΔBEC =
´ EC ´ h =
⇒ ´ 17 ´ h =
or h = 24 m.
Now area of trapezium = (sum of parallel sides) × height
\\\\ Area of trapezium = (60 + 77) ´ 24 = 1644 m2.
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