Answer :

Let, whole surface area of the toy = x m2


According to problem,


x × 2.1 = 429


x = 429/2.1


x = 204.286


Base diameter of the toy = 10 cm


base radius of the toy, r = 10/2 = 5 cm


Let, slant height = l cm


According to problem,


πr2 + πrl = 204.286


22/7(52 + 5l) = 204.286


5l + 25 = 65


5l = 40


l = 8


slant height = 8 cm


height = √(l2 – r2)= √(82 – 52) = √(64 – 25) = 6.24 cm


Volume of the toy,


= πr2h/3


= 22/7 × 52 × 6.24/3


= 163.43 m3


Quantity of wood required to make the toy = 163.43 m3


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Right Circular Cone And FrustumRight Circular Cone And FrustumRight Circular Cone And Frustum43 mins
Right Circular CylinderRight Circular CylinderRight Circular Cylinder45 mins
Magnetic Field of Circular ConductorMagnetic Field of Circular ConductorMagnetic Field of Circular Conductor41 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

If the height andWest Bengal Board - Mathematics

If the ratio of tWest Bengal Board - Mathematics

A heap of wheat iWest Bengal Board - Mathematics

Keeping the radiuWest Bengal Board - Mathematics

In a right circulWest Bengal Board - Mathematics

The length of theWest Bengal Board - Mathematics

Let us fill in thWest Bengal Board - Mathematics

The numerical valWest Bengal Board - Mathematics

Let us write whetWest Bengal Board - Mathematics

The curved surfacWest Bengal Board - Mathematics