Q. 8

The length of a string between a kite and a point on the ground is 90 meters. If the string makes an angle θ with the ground level such that tanθ =15/8, how high is the kite? Assume that there is no slack in the string.

Let AB be the height of kite.

Given:

To find: The length of AB.

Formula Used:

Explanation:

Let the height of string = “h” m

As we know,

In ΔPQR,

Perpendicular = PQ = 15

Base =QR = 8

According to Pythagoras theorem,

PR2 = PQ2 + QR2

PR2 = 152 + 82

PR2 = 225 + 64

PR2 = 289

PR = √289

PR = 17

As,

sin θ =

In ∆ABC,

17h = 90×15

79.41 m

Therefore, length of string = 79.41 m.

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