Q. 85.0( 1 Vote )

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Answer :

Cos2x=(√3-√3sin x)2

1-sin2x = 3+3sin2x-6sin x

4sin2x-6sin x+2=0

2sin2x-3sin x+1=0

sin x = 1 or 0.5

We know,

x = nπ + (-1)nθ Therefore, the values of x are So, these values are obtained for different value of n from the equation So, Option B

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