Q. 85.0( 1 Vote )

# Mark the Correct alternative in the following:

The general value of x satisfying the equation is given by

A.

B.

C.

D.

Answer :

Cos^{2}x=(√3-√3sin x)^{2}

1-sin^{2}x = 3+3sin^{2}x-6sin x

4sin^{2}x-6sin x+2=0

2sin^{2}x-3sin x+1=0

sin x = 1 or 0.5

We know,

x = nπ + (-1)^{n}θ

Therefore, the values of x are

So, these values are obtained for different value of n from the equation

So, Option B

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