Q. 85.0( 1 Vote )
Let be a rational number, say where q â 0 and p and q have no common factor.
Taking cube both sides
Since 1 3 = 1 , and 2 3 = 8, it follows that
Then q > 1 because if q = 1 then will be an integer, and there is no integer between 1 and 2.
being an integer, 6q 2 is an integer, and since q > 1 and q does not have a common factor with p and consequently with p 3 .
So, is not an integer.
There is contradiction in our assumption therefore is an irrational number.
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