Answer :


Given, AC BD and ABCD is the parallelogram so its diagonals bisects each other at O


AO = OC = 4cm


BO = OD = 3cm


Now in Δ AOB


AO = 4cm


BO = 3cm


And AOB = 90° so its right angled triangle


And AB is the hypotenuse


AB2 = AO2 +OB2


AB =


AB =


AB = √ 25


AB =5 cm


Similarly, BC = DC = AD = 5cm


Since all the sides are equal and the diagonals bisects each other at 90°


the given parallelogram is a rhombus


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