Answer :

Let the number of children = x

and the amount distributed by Seema for one student = ₹y

According to question,

Condition 1:

(x – 8)(y + 10) = xy

⇒ xy + 10x – 8y – 80 = xy

⇒ 10x – 8y = 80

⇒ 5x – 4y = 40 …(i)

Condition 2:

(x + 16)(y – 10) = xy

⇒ xy – 10x + 16y – 160 = xy

⇒ -10x + 16y = 160

⇒ -5x + 8y = 80 …(ii)

It is given that we have to solve this by matrix method.

So, we know that AX = B

and here,

AX = B ⇒ X = A^{-1}B

Now, we calculate A^{-1}

So,

⇒ x = 32 and y = 30

Hence, the number of students = 32

Amount given to each student = ₹30

Value reflected by Seema’s decision is that one should help to

needy the person.

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