Answer :

Given,

BAC = 40°


ACB = 65°


According to figure,


ACE = 40° [Alternate angles]


ACB + ACE = x° [Alternate angles]


x° = 65° + 40°


x = 105°

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

The sides BC, BA RS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

The angles of a tRS Aggarwal & V Aggarwal - Mathematics

In ΔABC, <span laRS Aggarwal & V Aggarwal - Mathematics

In ΔABC, BD <spanRS Aggarwal & V Aggarwal - Mathematics

In the given figuRS Aggarwal & V Aggarwal - Mathematics

In a ΔABC its is RS Aggarwal & V Aggarwal - Mathematics

Side BC of ΔABC hRS Aggarwal & V Aggarwal - Mathematics

An exterior angleRS Aggarwal & V Aggarwal - Mathematics