Q. 84.3( 26 Votes )

# In figure 3.61, chords AC and DE intersect at B. If ∠ ABE = 108°, m(arc AE) = 95°, find m(arc DC).

Answer :

Given ∠ ABE = 108°, m(arc AE) = 95°

Using the property of the secant,

⇒m(arc DC) = 108° × 2 – 95°

⇒m(arc DC) = 121°

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