Q. 84.3( 26 Votes )

In figure 3.61, chords AC and DE intersect at B. If ABE = 108°, m(arc AE) = 95°, find m(arc DC).



Answer :

Given ABE = 108°, m(arc AE) = 95°


Using the property of the secant,




m(arc DC) = 108° × 2 – 95°


m(arc DC) = 121°


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