Q. 84.8( 5 Votes )

In Fig. 10.75, Δ

Answer :

Given:


AR = 4 cm


BR = 3 cm


AC = 11 cm


Property: If two tangents are drawn to a circle from one external point, then their tangent segments (lines joining the external point and the points of tangency on circle) are equal.


Using the above property,


AR = AQ = 4 cm (tangent from A)


BR= BP (tangent from B)


And,


CP = CQ (tangent from C)


Also,


CQ = CA – AQ = 11 cm – 4 cm = 7 cm


Now,


BC = BP + PC


= BR + CQ [ BR = BP and CP = CQ = 7 cm]


= 3 cm + 7 cm


= 10 cm


Hence, BC = 10 cm


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