Q. 8

# If x + y = 12 and

x + y = 12

y = 12-x …Equation (i)

xy = 32

Putting the value of y from above Equation (i) we get

x(12-x) = 32

12x-x2 = 32

x2-12x + 32 = 0

Solving the above equation by the method of factorization we get

x2-8x-4x + 12 = 0

x(x-8)-4(x-8) = 0

(x-4)(x-8) = 0

x = 4,8

When x = 4, y = 8

x2 + y = 24

When x = 8, y = 4

x2 + y = 68

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