Q. 84.1( 18 Votes )

If (x-2) is a factor of x3 – mx2 + 10x - 20 then find the value of m.

Answer :

Put x = 2 throughout the polynomial and equate it to zero as x -2 is the factor of the given polynomial.

(2)3 – m × (2)2 + 10 × 2 – 20 = 0


8 – 4m + 20 – 20 = 0


4m = 8


m = 2


So for x-2 to be the factor of the given polynomial, the value of m = 2.


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