Answer :

Given that,

BC produced on both sides

We know that,

A + ABC + ACB = 180o (i)

ABD = A + ACB (Exterior angle theorem) (ii)

ACE = A + ABC (Exterior angle theorem) (iii)

Adding (ii) and (iii), we get

ABD + ACE = A + (A + ACB + ACB)

ABD + ACE = A + 180o

(ABD + ACE) - A = 180o

Thus, between the sum of the exterior angles so formed and A is 180o.

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