Q. 84.1( 13 Votes )

# If perimeter of a

Answer :

Given, perimeter of a rhombus is 20 cm. and length of its one diagonal is 6 cm

Side AB =

⟹ AB =

⟹ AB = 5cm

The diagonal AC =6cm

Hence, AO = 3cm

∠AOB = 90 ( the two diagonals of rhombus perpendicular bisected to each other)

Hence, OB^{2}=AB^{2}−AO^{2}

⟹ OB^{2}=5^{2}−3^{2}

⟹ OB = 4cm

∴ BD = 4×2

⟹ BD = 8cm

∴ Area of the Rhombus = ×8×6

= 24 sq.cm

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