# If perimeter of a

Given, perimeter of a rhombus is 20 cm. and length of its one diagonal is 6 cm

Side AB =

AB =

AB = 5cm

The diagonal AC =6cm

Hence, AO = 3cm

AOB = 90 ( the two diagonals of rhombus perpendicular bisected to each other)

Hence, OB2=AB2−AO2

OB2=52−32

OB = 4cm

BD = 4×2

BD = 8cm

Area of the Rhombus = ×8×6

= 24 sq.cm

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