Answer :

Given, perimeter of a rhombus is 20 cm. and length of its one diagonal is 6 cm


Side AB =


AB =


AB = 5cm


The diagonal AC =6cm


Hence, AO = 3cm


AOB = 90 ( the two diagonals of rhombus perpendicular bisected to each other)


Hence, OB2=AB2−AO2


OB2=52−32


OB = 4cm


BD = 4×2


BD = 8cm


Area of the Rhombus = ×8×6


= 24 sq.cm


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Angle Sum Property of a TriangleAngle Sum Property of a TriangleAngle Sum Property of a Triangle49 mins
Work and Types of Work doneWork and Types of Work doneWork and Types of Work done40 mins
Kinetic and Potential EnergyKinetic and Potential EnergyKinetic and Potential Energy39 mins
President and his PowersPresident and his PowersPresident and his Powers57 mins
Construction-2Construction-2Construction-244 mins
Construction-1Construction-1Construction-145 mins
PYQ's Practice -ConstructionPYQ's Practice -ConstructionPYQ's Practice -Construction47 mins
Conservation of EnergyConservation of EnergyConservation of Energy41 mins
Introduction to Lines and AnglesIntroduction to Lines and AnglesIntroduction to Lines and Angles52 mins
Probability-2Probability-2Probability-246 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Area of field in West Bengal Mathematics

The base of a parWest Bengal Mathematics

If perimeter of aWest Bengal Mathematics

The area of fieldWest Bengal Mathematics

In a quadrilateraWest Bengal Mathematics

In parallelogram West Bengal Mathematics

The length of oneWest Bengal Mathematics

If the lengWest Bengal Mathematics

The length West Bengal Mathematics

If the lengWest Bengal Mathematics