Q. 8

If cosec A= 2, find the value of

Answer :



As cosec = Hypotenuse/perpendicular


AC = 2 , BC = 1


In right angled ΔABC by Pythagoras theorem,


AC2 = AB2 + BC2
(2)2 = 12 + BC2
BC2 = 4 – 1


= 3


BC = √3 


As tan θ = perpendicular/base


Sin θ = perpendicular/hypotenuse


cos θ = base/hypotenuse

tan A = (1/√3)
sin A = (1/2)
cos A = (√3/2)







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