Answer :

Given,


tan θ = 1/√5


8.bmp


In ∆ ABC,


AC2 = AB2 + BC2


AC2 = 12 + (√5)2


AC2 = 1 + 5 = 6


AC = √6


We have,


cosec θ = AC/AB = √6/1


sec θ = AC/BC = √6/√5


Now,






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