Answer :

Step 1: The perpendicular AD is taken as the base and the 5cm length is constructed.

Step 2: An angle of 45° is constructed at A to form <XAC and 60° to form <YAB

The points C and B fall on the line perpendicular through D

∆ABC is the required triangle

<B = 60°

<C = 45°

AD = 5cm

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