Q. 85.0( 3 Votes )

# A wooden box has inner dimensions l =6 m, b =8 m and h =9 m and it has a uniform thickness of 10 cm. The lateral surface of the outer side has to be painted at the rate of Rs. 50/ m^{2}. What is the cost of painting?

Answer :

Given, a wooden box has inner dimensions l =6 m, b =8 m and h =9 m and a uniform thickness of

10 cm.

∴ Length = 6 + 0.20

= 6.2 m

∴ Breadth = 8 + 0.20

= 8.2 m

∴ Height = 9 + 0.20

= 9.2 m

We know, **Lateral Surface Area of cuboid = 2h(l+b)**

Lateral Surface Area = 2h(l+b)

= 2×9.2×(6.2+8.2)

= 18.4×14.4

= 264.96 m^{2}

The rate of painting lateral surface of the outer side = Rs. 50/m^{2}

∴ Cost of painting = Rs. 50 × 264.96

= Rs. 13248

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