Q. 83.7( 3 Votes )

A chord of a circ

Answer :


Let PQ be the chord of a circle subtending a right angle at the centre of the circle.


Also, radius of circle = OP = OQ = 5 cm


Now, Δ OPQ is a right angled triangle.


We know that by Pythagoras Theorem, AC2 = AB2 + BC2


In Δ OPQ, PQ2 = OP2 + OQ2


PQ2 = 52 + 52


PQ2 = 25 + 25


PQ2 = 50


PQ = 5√2


The length of the chord is 5√2 cm.

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