# 11, 8, 5, 2, . . . In this A.P. which term is number – 151?

By, given A.P. 11, 8, 5, 2, . . .

we know that

a = 11, t1 = 8, t2 = 5

Thus, d = t2 – t1 = 5 – 8 = – 3

Given: tn = – 151

Now, By using nth term of an A.P. formula

tn = a + (n – 1)d

we can find value of “n”

Thus, on substituting all the value in formula we get,

– 151 = 11 + (n – 1)× ( – 3)

– 151 – 11 = (n – 1)× ( – 3)

– 162 = (n – 1) × ( – 3) n = 54 + 1 = 55

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