Q. 7 B5.0( 4 Votes )

# If <span lang="EN

Formula used.

(a – b)2 = a2 – 2ab + b2

3x2 – 5xy + 3y2

Add and subtract xy to the equation.

3x2 – 5xy + 3y2 [ + xy – xy]

3x2 – 6xy + 3y2 + xy

3[x2 – 2xy + y2] + xy

3[x-y]2 + xy

x = 2 + √3

y = 2 – √3

xy = (2 + √3) × ( 2-√3)

xy = (2)2 – (√3)2

= 4 – 3

= 1

x – y = 2 + √3 – [2-√3]

x – y = 2√3

Putting the values we get;

3[2√3]2 + 1

3 + 1

36 + 1 = 37

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