Q. 794.1( 11 Votes )

Two taps running

Answer :

Let the time taken by faster tap to fill tank is x hours,


In 1 hour, part of tank filled


In , part of tank filled


Therefore, time taken by slower tap is (x + 3) hours


In 1 hour, part of tank filled


In , part of tank filled


As, both taps fill the whole tank in hours.


We have,






13x2 + 39x = 120 + 80xd


13x2 - 41x - 120 = 0


13x2 - 65x + 24x - 120 = 0


13x(x - 5) + 24(x - 5) = 0


(13x + 24)(x - 5) = 0


or x = 5


But time can't be negative, therefore x = 5 hours


Time taken by faster tap = x = 5 hours


Time taken by slower tap = x + 3 = 8 hours.

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