Q. 73.9( 12 Votes )

# Let us solve the following simultaneous linear equations in two variables by applying cross multiplication method.

Answer :

⇒ 4(x + 2) + 7(y - x) = 28(2x - 8) (Multiplying both sides by 28)

⇒ 59x - 7y - 232 = 0

⇒ (2y - 3x) + 6y = 3(3x + 4) (Multiplying both sides by 3)

⇒ 12x - 8y + 12 = 0

⇒ 3x - 2y + 3 = 0

To solve the equation by cross multiplication method, we use:

Putting the values, we get:

So, and

⇒ x = 5 and y = 9

Rate this question :

Let us solve the following simultaneous linear equations in two variables by applying cross multiplication method.

ax + by = 1

West Bengal Mathematics

Let us solve the following simultaneous equations in two variables by the method of substitution and check whether the solutions satisfy the equations.

West Bengal Mathematics

Let us solve the following simultaneous equations in two variables by the method of substitution.

2(x – y) = 3

5x + 8y = 14

West Bengal MathematicsLet us write the area of the triangle formed by the graph of the equation 3x + 4y = 12 and the axes.

West Bengal MathematicsLet us draw the graph of the three equations x = 4, y = 3 and 3x + 4y = 12 and determine the area of the triangle formed by the graph.

West Bengal MathematicsLet us draw the graph of the following simultaneous linear equations and determine the coordinates of the point of intersection.

3x – 5y = 16 and 2x – 9y = 5

West Bengal MathematicsLet us draw the graph of the following simultaneous linear equations and determine the coordinates of the point of intersection.

y = 5 and 2x + 3y = 11

West Bengal Mathematics