Q. 74.2( 6 Votes )

# Write the value of cosec^{2} (90° − θ) − tan^{2}θ.

Answer :

To find: cosec^{2} (90° − θ) − tan^{2}θ

∵ cosec (90° – θ) = sec θ

∴ cosec^{2} (90° – θ) = sec^{2} θ

⇒ cosec^{2} (90° θ) − tan^{2} θ = sec^{2} θ – tan^{2} θ

Now, ∵ 1 + tan^{2} θ = sec^{2} θ

∴ cosec^{2} (90° − θ) − tan^{2} θ = sec^{2} θ – tan^{2} θ

= 1 + tan^{2} θ – tan^{2} θ = 1

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

Related Videos

Trigonometric Identities33 mins

Basic Concepts of Trigonometry45 mins

Champ Quiz | Trigonometric Identities33 mins

Smart Revision | Trigonometric Identities40 mins

Applying the Trigonometric Identities52 mins

NCERT | Trigonometric Identities52 mins

Trigonometric Identities44 mins

Solving NCERT Questions on Trigonometric Identities56 mins

Algebraic Identities48 mins

Quiz | Practice Important Questions on Trigonometrical Identities46 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation

RELATED QUESTIONS :

Prove the following identities :

tan^{4}θ + tan^{2}θ = sec^{4}θ – sec^{2}θ

Prove the following identities :

sin^{2} θ(1+ cot^{2} θ) = 1

Prove the following identities :

cos^{2} A (tan^{2} A+1) = 1

If sin 77° = x, then write the value of cos 77^{o} in terms of x.

If cos55° = x^{2}, then write the value of sin 55^{o} in terms of x.

If cos40^{o} = p, then write the value of sin 40^{o} in terms of p.