Q. 75.0( 1 Vote )

Write the points

Answer :

Given that f(x) = |loge x| where



Clearly f(x) is differentiable for x>1 and x<1. So, we will check the differentiability at x = 1.


LHD at x =1,




RHD at x =1,




LHD ≠RHD


f(x) = |loge x| is not differentiable.


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