Given that f(x) = |loge x| where
Clearly f(x) is differentiable for x>1 and x<1. So, we will check the differentiability at x = 1.
LHD at x =1,
RHD at x =1,
∵ LHD ≠RHD
∴ f(x) = |loge x| is not differentiable.
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
RELATED QUESTIONS :
If <iMathematics - Exemplar