Q. 7

When <span lan A. -2, -6

B. 2 and -6

C. -2 and 6

D. 2 and 6

Answer :

Let p(x) = x3 -2(x2) + ax - b

q (x) = x2 -2x -3


r (x) = x - 6


Therefore,


f(x) = p (x) – r (x)


f(x) = x3 - 2x2 + ax - b - x - 6


= x3- 2x2 + (a - 1) x - (b - 6)


q(x) = x2 - 2x - 3


= (x + 1) (x - 3)


Thus,


(x + 1) and (x - 3) are factor of f (x)


a + b = 4


f (3) = 0


33 - 2 (3)2 + (a-1) 3 - b + 6 = 0


12 + 3a - b = 0


a = - 2, b = 6

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