Q. 74.5( 2 Votes )

# Three medians AD,

Answer :

Given: area of ABC is 36 sq cm

(i) As we know if three medians AD, BE and CF of a ΔABC intersect one another at the point G (centroid) then,

Area of ΔABC = 3 × Δ AGB

Area of ΔAGB =

Area of ΔAGB = 12 sq. cm

(ii) As we know if three medians AD, BE and CF of a ΔABC intersect one another at the point G (centroid) then,

Area of ΔABC = 6 × Δ GEC

Area of ΔGEC =

Area of ΔGEC = 6 sq. cm

(ii) As we know if three medians AD, BE and CF of a ΔABC intersect one another at the point G (centroid) then,

Area of ΔABC = 3 × Δ BDGF

Area of ΔBDGF =

Area of ΔBDGF = 12 sq. cm

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