Answer :


Given: area of ABC is 36 sq cm


(i) As we know if three medians AD, BE and CF of a ΔABC intersect one another at the point G (centroid) then,


Area of ΔABC = 3 × Δ AGB


Area of ΔAGB =


Area of ΔAGB = 12 sq. cm


(ii) As we know if three medians AD, BE and CF of a ΔABC intersect one another at the point G (centroid) then,


Area of ΔABC = 6 × Δ GEC


Area of ΔGEC =


Area of ΔGEC = 6 sq. cm


(ii) As we know if three medians AD, BE and CF of a ΔABC intersect one another at the point G (centroid) then,


Area of ΔABC = 3 × Δ BDGF


Area of ΔBDGF =


Area of ΔBDGF = 12 sq. cm


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