Answer :

**Given:** Bag A contains 3 white and 4 red balls while Bag B contains 4 white and 3 red balls

Let E_{1} = Selecting bag A, E_{2} = selecting bag B

Probability of selecting the bag is given by

Now the probability of the balls drawn from bag A

Total number of ways of getting 2 white and 1 red ball from bag A = ^{3}C_{2}^{4}C_{1} = 12

Total possible outcome is = ^{7}C_{3} = 35

So

Now the probability of the balls drawn from bag B

Total number of ways of getting 2 white and 1 red ball from bag B = ^{4}C_{2}^{3}C_{1} = 18

So,

Probability of the balls being drawn from bag B is given by

**Formula:** Bayes theorem

**Hence, probability that these were drawn from bag B**

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