Q. 75.0( 1 Vote )

# Mark the correct alternative in the following:The range of f(x) = cos [x], for -π/2< x <π/2 isA. {-1, 1, 0}B. {cos 1, cos 2, 1}C. {cos 1, -cos 1, 1}D. [-1, 1]

Answer :

[x]= -2

f(x)= cos[x]= cos(-2)

= cos2

because cos(-x)= cos(x)

for-1 ≤x<0

[x]=-1

f(x)= cos[x]

=cos(-1)

= cos1

for 0 ≤x< 1

[x]=0

f(x) = cos 0

=1

[x]=1

f(x)=cos 1

Therefore, R(f) = {1, cos 1,cos 2}

Option B is correct.

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