Q. 7

# Solve the following quadric equation for x :

4x^{2} + 4bx – (a^{2} – b^{2}) = 0

Answer :

Equation can be re - written as

4x^{2} + 4bx + (b^{2} – a^{2}) = 0

4x^{2} + 2(b - a)x + 2(b + a)x + (b - a)(b + a) = 0 [ as x^{2} - y^{2} = (x + y) (x - y) ]

2x(2x + b - a) + (b + a)(2x + b - a) = 0

(2x + b + a)(2x + b - a) = 0

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