Solve each of the

On cross multiplication

2(a - 8) = 3(a - 3)

2a - 16 = 3a - 3

On transposing constant terms to RHS and variables to LHS, we get

2a - 3a = 16 - 9

-a = 7

a = -7

Check:

Taking LHS

On substituting a = -7, we get

Taking RHS

On substituting a = -7, we get

We got LHS = RHS