Q. 74.4( 14 Votes )

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Answer :

Steps of Construction:

1. We draw a triangle ABC of given dimensions.

2. We draw a perpendicular bisector of side AB which intersects AB at D.

3. Join C to D.

4. Draw a line parallel to AB through C by completing the parallelogram ACQB.

5. As we have to draw a rectangle of same area. We can use the perpendicular bisector drawn through D.

6. The perpendicular bisector cuts parallel line through C at E.

7. From E, cut an arc of length DB on the parallel line.

8. Mark the point as F.

9. Join F to B.

10. DBFE is the required rectangle.

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<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

Pritam drew a quaWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics