Answer :

Steps of Construction:


1. We draw a triangle ABC of given dimensions.



2. We draw a perpendicular bisector of side AB which intersects AB at D.


3. Join C to D.



4. Draw a line parallel to AB through C by completing the parallelogram ACQB.



5. As we have to draw a rectangle of same area. We can use the perpendicular bisector drawn through D.


6. The perpendicular bisector cuts parallel line through C at E.


7. From E, cut an arc of length DB on the parallel line.


8. Mark the point as F.


9. Join F to B.


10. DBFE is the required rectangle.



Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

Pritam drew a quaWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics

<span lang="EN-USWest Bengal Mathematics