In the given figure, O is a point inside m a ΔMNP such that ∠MOP = 90°, OM = 16 cm and OP = 12 cm. If MN = 21 cm and ∠NMP = 90° then NP = ?A. 25 cmB. 29 cmC. 33 cmD. 35 cm

The ΔMOP is right angled at O so MP is hypotenuse

(MP)2 = (OM)2 + (OP)2

(MP)2 = (16) 2 + (12)2

(MP)2 = 400

MP = 20 cm

Δ NMP is right angled at M so NP is the hypotenuse so

(NP)2 = (21)2 + (20)2

NP = 29

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