# In figure 2.27, if line AB || line CF and line BC || line ED then prove that ∠ ABC = ∠ FDE

Given: Line AB CF and line BC ED

To find: ABC = FDE

Construction: G and h in diagram.

AB CD and BC is transversal both

So, ABC = PCG (linear pair angle)

BC ED and PF is transversal line to both

So, ECG = CDH

CD = FDE (Both angle is opposite)

ABC = FDE (hence proved)

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