Q. 7 5.0( 1 Vote )

In figure 1, common tangents AB and CD to the two circles with centres O1 and O2 intersect at E. Prove that AB = CD.


Answer :

From the given figure,

AE = CE [Tangents drawn from an external point to the same circle are equal]


EB = ED [Tangents drawn from an external point to the same circle are equal]


AE + EB = CE + ED


AB = CD


Hence Proved.


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