Q. 74.0( 30 Votes )

# In figure 1.75, A – D – C and B – E – C seg DE || side AB If AD = 5, DC = 3, BC = 6.4 then find BE.

Answer :

By Basic Proportionality Theorem-

⇒

⇒

⇒ 3x = 32-5x

⇒ 8x = 32

⇒ x = 4 = BE

Rate this question :

Solve Question:

The ratio of the areas of two triangles with the common base is 4:3. Height of the larger triangle is 2 cm, then finds the corresponding height of the smaller triangle.

Maharashtra Board - Geometry PapersSolve any five sub-questions:

ΔDEF ∼ ΔMNK. If DE = 5, MN = 6, then find the value of

Maharashtra Board - Geometry PapersSolve any two sub-questions:

Prove that “That ratio of areas of two similar triangles is equal to the square of the ratio of their corresponding sides.”

Maharashtra Board - Geometry PapersIn figure 1.75, A – D – C and B – E – C seg DE || side AB If AD = 5, DC = 3, BC = 6.4 then find BE.

MHB - Mathematics Part-2

In figure 1.74, PM = 10 cm A(Δ PQS) = 100 sq.cm A (ΔQRS) = 110 sq.cm then find NR.

MHB - Mathematics Part-2

Solve sub-questions:

In the following figure, RP: PK = 3:2, find the value of A(ΔTRP) : A(ΔTPK).

Maharashtra Board - Geometry Papers

If ΔABC ~ ΔPQR, A (ΔABC) = 80, A(ΔPQR) = 125, then fill in the blanks.

MHB - Mathematics Part-2