Q. 75.0( 3 Votes )

In Fig. 16.198, <

Answer :

Given that,

A is the centre of the circle, then


AB = AD


ABCD is a parallelogram, then


AD BC, AB CD


CDE is a straight line, then


AB CE


Let,


BEC = ABE = x’ (Alternate angle)


We know that,


The angle substended by an arc of a circle at the centre double the angle are angle substended by it at any point on the remaining part of circle


BAD = 2 BEC


BAD = 2x’


In a rhombus opposite angles are equal to each other


BAD = BCD = 2x’


Now, we have to find


=


=


=


Hence,


BCD: ABE is 2: 1


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