# In Fig. 16.198, <

Given that,

A is the centre of the circle, then

ABCD is a parallelogram, then

CDE is a straight line, then

AB CE

Let,

BEC = ABE = x’ (Alternate angle)

We know that,

The angle substended by an arc of a circle at the centre double the angle are angle substended by it at any point on the remaining part of circle

In a rhombus opposite angles are equal to each other

Now, we have to find =  =  = Hence,

BCD: ABE is 2: 1

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