# <span lang="EN-US

The figure is attached below:

BN and AM are the angle bisectors of angle B and A respectively. Given C = 70°

In a triangle we know sum of interior angles is 180°

In ΔABC

A + B + C = 180°

A + B = 180° - 70°

A + B = 110°

Now in ΔAOB

AO is the bisector of A

BO is the bisector of B

OAB = A/2 and OBA = B/2

OAB + OBA + AOB = 180°

A/2 + B/2 + AOB = 180°

AOB = 180° - (A + B)/2

AOB = 180° - 110°/2 = 180° - 55°

AOB = 125°

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