Answer :

It is given in the question that,

In , we have


B = 35o


C = 65o


Also the bisector AD of BAC meets at D


A + B + C = 180o


A + 35o + 65o = 180o


A = 180o – 100o


A = 80o


As, AD is the bisector of BAC


BAD = CAD = 40o


In , we have


BAD > ABD


BD > AD


Also, in


ACD > CAD


AD > CD


Hence, BD > AD > CD


Option (B) is correct

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