# If and xyz = 1, then let us show that a + b + c = 0.

Given and xyz = 1

Let

Therefore,

…eq(1)

…eq(2)

…eq(3)

Now, xyz = 1

(from eq(1), eq(2)and eq(3))

We know that if base of the exponents are same then the powers are also equal.

Therefore, a + b + c = 0.

Hence the relation is proved.

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