Q. 74.4( 24 Votes )

If and xyz = 1, then let us show that a + b + c = 0.

Answer :

Given and xyz = 1

Let


Therefore,


…eq(1)



…eq(2)



…eq(3)


Now, xyz = 1



(from eq(1), eq(2)and eq(3))




We know that if base of the exponents are same then the powers are also equal.


Therefore, a + b + c = 0.


Hence the relation is proved.


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