Q. 74.4( 24 Votes )
If
and xyz = 1, then let us show that a + b + c = 0.
Answer :
Given and xyz = 1
Let
Therefore,
…eq(1)
…eq(2)
…eq(3)
Now, xyz = 1
(from eq(1), eq(2)and eq(3))
We know that if base of the exponents are same then the powers are also equal.
Therefore, a + b + c = 0.
Hence the relation is proved.
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